n(2-5n)+5(n^2-2)=0

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Solution for n(2-5n)+5(n^2-2)=0 equation:


Simplifying
n(2 + -5n) + 5(n2 + -2) = 0
(2 * n + -5n * n) + 5(n2 + -2) = 0
(2n + -5n2) + 5(n2 + -2) = 0

Reorder the terms:
2n + -5n2 + 5(-2 + n2) = 0
2n + -5n2 + (-2 * 5 + n2 * 5) = 0
2n + -5n2 + (-10 + 5n2) = 0

Reorder the terms:
-10 + 2n + -5n2 + 5n2 = 0

Combine like terms: -5n2 + 5n2 = 0
-10 + 2n + 0 = 0
-10 + 2n = 0

Solving
-10 + 2n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 2n = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 2n = 0 + 10
2n = 0 + 10

Combine like terms: 0 + 10 = 10
2n = 10

Divide each side by '2'.
n = 5

Simplifying
n = 5

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